x^2+2*b*x+3*c=0

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Solution for x^2+2*b*x+3*c=0 equation:


Simplifying
x2 + 2b * x + 3c = 0

Multiply b * x
x2 + 2bx + 3c = 0

Reorder the terms:
2bx + 3c + x2 = 0

Solving
2bx + 3c + x2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3c' to each side of the equation.
2bx + 3c + -3c + x2 = 0 + -3c

Combine like terms: 3c + -3c = 0
2bx + 0 + x2 = 0 + -3c
2bx + x2 = 0 + -3c
Remove the zero:
2bx + x2 = -3c

Add '-1x2' to each side of the equation.
2bx + x2 + -1x2 = -3c + -1x2

Combine like terms: x2 + -1x2 = 0
2bx + 0 = -3c + -1x2
2bx = -3c + -1x2

Divide each side by '2x'.
b = -1.5cx-1 + -0.5x

Simplifying
b = -1.5cx-1 + -0.5x

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